Distance from Davinópolis to Pitt
Davinópolis → Pitt
5,550 km
≈ 3,449 miles · 2,997 nautical miles
DavinópolisPitt
7 h 24 min
Flight (if direct)
3 d 8 h
Driving time (est.)
north-northwest
Direction (328°)
-2 h
Time difference
About this route
The straight-line distance from Davinópolis to Pitt is 5,550 km (3,449 miles). At this scale, air travel is the practical choice — if a direct flight operates, it would take around 7 h 24 min.
The geographic midpoint of the route lies near Oxford, Canada.
| Metric | Value |
|---|---|
| Straight-line distance | 5,550 km / 3,449 mi / 2,997 nmi |
| Estimated road distance | 7,215 km / 4,483 mi |
| Estimated flight time | 7 h 24 min — if a direct flight operates (805 km/h cruise) |
| Estimated driving time | 3 d 8 h (90 km/h average) |
| Initial bearing | 328° — north-northwest |
| Geographic midpoint | Near Oxford, Canada |
| Time difference | Pitt is -2 h (UTC-03:00 → UTC-05:00) |
| Davinópolis coordinates | -5.5701, -47.3064 |
| Pitt coordinates | 35.5935, -77.3747 |
Flight and driving times are estimates. A direct flight may not be available between Davinópolis and Pitt — actual travel can require connections, and road routes are longer than the straight line.
↔ Reverse: Pitt to Davinópolis All distances from Davinópolis All distances from Pitt
Distance from Davinópolis to places near Pitt
Frequently asked questions
How far is Pitt from Davinópolis?
Pitt is 5,550 km (3,449 miles) from Davinópolis measured as a straight line (great-circle distance). The estimated road distance is about 7,215 km (4,483 mi).
How long is the flight from Davinópolis to Pitt?
If a direct flight operates between Davinópolis and Pitt, it would take approximately 7 h 24 min, based on an average cruising speed of 805 km/h (500 mph) plus 30 minutes for take-off and landing. Note that a direct flight may not be available on this route — actual travel may require a connecting flight or another mode of transport.
What is the time difference between Davinópolis and Pitt?
Pitt has 2 hours behind Davinópolis. Davinópolis uses UTC-03:00 and Pitt uses UTC-05:00.
What is the halfway point between Davinópolis and Pitt?
The geographic midpoint between Davinópolis and Pitt is near Oxford, Canada, roughly 2,775 km from each city.
In which direction is Pitt from Davinópolis?
Pitt lies to the north-northwest of Davinópolis, at an initial bearing of 328°.