Billable / Specific Code
ICD-10-CM M25.675 is the diagnosis code for Stiffness of left foot, not elsewhere classified. This code falls under the section "Other joint disorders" within Chapter 13 — Diseases of the musculoskeletal system and connective tissue (M00-M99). It is a billable/specific ICD-10-CM code that can be used to indicate a diagnosis for reimbursement purposes. Medical coders and healthcare providers use this code to document and classify diagnoses in electronic health records, insurance claims, and clinical databases.
Always refer to the official ICD-10-CM Tabular List for complete coding guidelines. Ensure documentation supports the specificity of the code selected. When in doubt, consult a certified medical coder or the latest CMS guidelines.
Understanding where M25.675 sits in the ICD-10-CM classification helps ensure proper coding:
Yes, M25.675 is a billable/specific ICD-10-CM code that can be used to indicate a diagnosis for reimbursement purposes.
M25.675 is the ICD-10-CM diagnosis code for "Stiffness of left foot, not elsewhere classified". It is used by healthcare providers to classify and document this condition in medical records and insurance claims.
The parent code of M25.675 is M25.67 ("Stiffness of ankle and foot, not elsewhere classified"). M25.675 provides a more specific classification within this category.
M25.675 is located in Section M20-M25 — "Other joint disorders" within Chapter 13 of the ICD-10-CM Tabular List.
Use M25.675 when the patients documented diagnosis matches "Stiffness of left foot, not elsewhere classified" and the clinical documentation supports this level of specificity. Always verify with the latest ICD-10-CM guidelines and payer requirements.
The ICD-10-CM code for Stiffness of left foot, not elsewhere classified is M25.675.
Yes, M25.675 can be used as a primary diagnosis code since it is billable and specific.
M25.675 is in Chapter 13 of the ICD-10-CM Tabular List.
Yes, M25.675 is a valid ICD-10-CM code for the 2026 fiscal year, subject to official CMS updates.