Billable / Specific Code
ICD-10-CM S65.312 is the diagnosis code for Laceration of deep palmar arch of left hand. This code falls under the section "Injuries to the wrist, hand and fingers" within Chapter 19 — Injury, poisoning and certain other consequences of external causes (S00-T88). It is a billable/specific ICD-10-CM code that can be used to indicate a diagnosis for reimbursement purposes. Medical coders and healthcare providers use this code to document and classify diagnoses in electronic health records, insurance claims, and clinical databases.
Always refer to the official ICD-10-CM Tabular List for complete coding guidelines. Ensure documentation supports the specificity of the code selected. When in doubt, consult a certified medical coder or the latest CMS guidelines.
Understanding where S65.312 sits in the ICD-10-CM classification helps ensure proper coding:
Yes, S65.312 is a billable/specific ICD-10-CM code that can be used to indicate a diagnosis for reimbursement purposes.
S65.312 is the ICD-10-CM diagnosis code for "Laceration of deep palmar arch of left hand". It is used by healthcare providers to classify and document this condition in medical records and insurance claims.
The parent code of S65.312 is S65.31 ("Laceration of deep palmar arch"). S65.312 provides a more specific classification within this category.
S65.312 is located in Section S60-S69 — "Injuries to the wrist, hand and fingers" within Chapter 19 of the ICD-10-CM Tabular List.
Use S65.312 when the patients documented diagnosis matches "Laceration of deep palmar arch of left hand" and the clinical documentation supports this level of specificity. Always verify with the latest ICD-10-CM guidelines and payer requirements.
The ICD-10-CM code for Laceration of deep palmar arch of left hand is S65.312.
Yes, S65.312 can be used as a primary diagnosis code since it is billable and specific.
S65.312 is in Chapter 19 of the ICD-10-CM Tabular List.
Yes, S65.312 is a valid ICD-10-CM code for the 2026 fiscal year, subject to official CMS updates.