ICD-10-CM R79.0 is the diagnosis code for Abnormal level of blood mineral. This code falls under the section "Abnormal findings on examination of blood, without diagnosis" within Chapter 18 — Symptoms, signs and abnormal clinical and laboratory findings, not elsewhere classified (R00-R99). It is a billable/specific ICD-10-CM code that can be used to indicate a diagnosis for reimbursement purposes. Medical coders and healthcare providers use this code to document and classify diagnoses in electronic health records, insurance claims, and clinical databases.
The following conditions should never be coded at the same time as R79.0. They are mutually exclusive:
Understanding where R79.0 sits in the ICD-10-CM classification helps ensure proper coding:
Yes, R79.0 is a billable/specific ICD-10-CM code that can be used to indicate a diagnosis for reimbursement purposes.
R79.0 is the ICD-10-CM diagnosis code for "Abnormal level of blood mineral". It is used by healthcare providers to classify and document this condition in medical records and insurance claims.
The parent code of R79.0 is R79 ("Other abnormal findings of blood chemistry"). R79.0 provides a more specific classification within this category.
R79.0 is located in Section R70-R79 — "Abnormal findings on examination of blood, without diagnosis" within Chapter 18 of the ICD-10-CM Tabular List.
Use R79.0 when the patients documented diagnosis matches "Abnormal level of blood mineral" and the clinical documentation supports this level of specificity. Always verify with the latest ICD-10-CM guidelines and payer requirements.
The ICD-10-CM code for Abnormal level of blood mineral is R79.0.
Yes, R79.0 can be used as a primary diagnosis code since it is billable and specific.
R79.0 is in Chapter 18 of the ICD-10-CM Tabular List.
Type 1 Excludes for R79.0 include: abnormal level of lithium (R78.89); disorders of mineral metabolism (E83.-); neonatal hypomagnesemia (P71.2) and more.
Yes, R79.0 is a valid ICD-10-CM code for the 2026 fiscal year, subject to official CMS updates.