Billable / Specific Code
ICD-10-CM H33.052 is the diagnosis code for Total retinal detachment, left eye. This code falls under the section "Disorders of choroid and retina" within Chapter 7 — Diseases of the eye and adnexa (H00-H59). It is a billable/specific ICD-10-CM code that can be used to indicate a diagnosis for reimbursement purposes. Medical coders and healthcare providers use this code to document and classify diagnoses in electronic health records, insurance claims, and clinical databases.
Always refer to the official ICD-10-CM Tabular List for complete coding guidelines. Ensure documentation supports the specificity of the code selected. When in doubt, consult a certified medical coder or the latest CMS guidelines.
Understanding where H33.052 sits in the ICD-10-CM classification helps ensure proper coding:
Yes, H33.052 is a billable/specific ICD-10-CM code that can be used to indicate a diagnosis for reimbursement purposes.
H33.052 is the ICD-10-CM diagnosis code for "Total retinal detachment, left eye". It is used by healthcare providers to classify and document this condition in medical records and insurance claims.
The parent code of H33.052 is H33.05 ("Total retinal detachment"). H33.052 provides a more specific classification within this category.
H33.052 is located in Section H30-H36 — "Disorders of choroid and retina" within Chapter 7 of the ICD-10-CM Tabular List.
H33.052 has 1918 sub-code(s) that provide more specific detail: A00, A01, A02, A03, A04 and more.
Use H33.052 when the patients documented diagnosis matches "Total retinal detachment, left eye" and the clinical documentation supports this level of specificity. Always verify with the latest ICD-10-CM guidelines and payer requirements.
The ICD-10-CM code for Total retinal detachment, left eye is H33.052.
Yes, H33.052 can be used as a primary diagnosis code since it is billable and specific.
H33.052 is in Chapter 7 of the ICD-10-CM Tabular List.
Yes, H33.052 is a valid ICD-10-CM code for the 2026 fiscal year, subject to official CMS updates.