ICD-10-CM M24.6 is the diagnosis code for Ankylosis of joint. This code falls under the section "Other joint disorders" within Chapter 13 â Diseases of the musculoskeletal system and connective tissue (M00-M99). It is a non-billable/non-specific ICD-10-CM code that should not be used for reimbursement. A more specific sub-code is required for billing. Medical coders and healthcare providers use this code to document and classify diagnoses in electronic health records, insurance claims, and clinical databases.
The following conditions should never be coded at the same time as M24.6. They are mutually exclusive:
The following conditions are not included in M24.6. If the patient has both, code each condition separately:
Understanding where M24.6 sits in the ICD-10-CM classification helps ensure proper coding:
No, M24.6 is a non-billable/non-specific code. You should use a more specific sub-code for billing and reimbursement.
M24.6 is the ICD-10-CM diagnosis code for "Ankylosis of joint". It is used by healthcare providers to classify and document this condition in medical records and insurance claims.
The parent code of M24.6 is M24 ("Other specific joint derangements"). M24.6 provides a more specific classification within this category.
M24.6 is located in Section M20-M25 â "Other joint disorders" within Chapter 13 of the ICD-10-CM Tabular List.
M24.6 has 1918 sub-code(s) that provide more specific detail: A00, A01, A02, A03, A04 and more.
Use M24.6 when the patients documented diagnosis matches "Ankylosis of joint" and the clinical documentation supports this level of specificity. Always verify with the latest ICD-10-CM guidelines and payer requirements.
The ICD-10-CM code for Ankylosis of joint is M24.6.
No, M24.6 is non-billable. Use a more specific sub-code for primary diagnosis billing.
M24.6 is in Chapter 13 of the ICD-10-CM Tabular List.
Type 1 Excludes for M24.6 include: stiffness of joint without ankylosis (M25.6-).
Yes, M24.6 is a valid ICD-10-CM code for the 2026 fiscal year, subject to official CMS updates.